The Interpretation of Non-Zero Mutual
Resistances
Application Note: The
Interpretation of Non-Zero Mutual Resistances in
PhysAPEX
Sept 16, 2008 ©
Physware, Inc. by Vikram Jandhyala and Swagato
Chakraborty
Physware’s accelerated system- in-package
extractor PhysAPEX rapidly creates accurate and large-scale
full-net RLGC models. This note discusses the physical
meaning of the mutual resistance terms generated.It is shown
that these terms have explicit correspondence to overlapping
ground returns at low frequency. The concept of high-frequency
induced-current-based mutual resistance is also shown to be
erroneous. Finally, the distinction between
transmission-line like nets, with a common ground, and
low-frequency conductor nets, is shown to be the reason for
the appearance of the mutual resistance
terms.
Consider two nets that share the same conductor. This might happen if
the two nets have a common ground reference which is modeled
explicitly. Explicit ground models are possible in PhysAPEX
and can be used because of the speed and scalability of the
solver. A simple
example is shown below.

Clearly, the two nets above share a
common conductor. The ground return paths may have an
overlap. In fact, in this case, the overlap will be
larger at lower frequencies where the return currents
tend to spread out and not follow a tight path under the
trace. In the low
frequency (quasi-static) case, we can write the
equivalent circuit (where the common part of the ground
return is shown as the middle segment. Assume we are
looking only at the resistive part of the
problem.

The voltages are with respect to the
central conductor (representing the shared ground), and the
currents are assumed to be directed away from the sources
towards the loads on the left.
Consider the conductance representation of
the two net case (the inverse of this 2X2 matrix will
provide the resistance matrix.

We use smaller case letters in the matrix
so as not to confuse with the conductance matrix associated
with dielectric losses. To find the off-diagonal term in the
first row, we will short the second port while exciting the
first with a unit positive voltage, i.e.

We now show that
this term will in general be non-zero. From KCL, first we see
that

Now we apply KVL around the two nets to
get:

And

From the
definition of
, the only way it
will be zero is if
is zero. From the
equation above, that implies
must be zero, and
therefore
is zero. Therefore
in the non-trivial case of non-zero current flow through net1,
the cross coupling term must be non-zero. In exactly the same
manner, it can be shown that
must be
non-zero.
As is seen, the only way that the
off-diagonal term is zero is when there is no current
through the ground return. This only happens in the trivial
case when there is no current flow anywhere in the circuit.
The non-zero off-diagonal terms in the inverse of the
resistance matrix hence lead to non-zero mutual terms in the
resistance matrix.
The physical reason for this non-zero
resistance, even at low frequencies (and DC) is the shared
ground return between the two nets. These two nets have been
setup in a transmission-line like topology, where there is a
shared reference conductor. In general, in an N+1
multiconductor line system, if the
0th
line is chosen as a
reference, the resistance matrix is an NXN matrix,
where all entries in the matrix (including
diagonal as well) are incremented by the value of the
resistance in the reference conductor path. This is
exactly the same effect happening in the 3D case
described here.
An alternative definition of ports, only
valid at quasi-static (and static) limits, would be to treat
every conductor separately, and define ports
across the conductors. Of course this port
definition is invalid (electrically large!) at high
frequencies. In that case, we would arrive at a 3X3
resistance matrix with only diagonal values. This is shown
below. Consider three conductors with ports defined across
the conductors.

This configuration will not have any
off-diagonal resistances, and the resistance matrix will
be

However, once there is a shared return
conductor, the resistance of the return conductor effects
every element of the resistance matrix, including the
off-diagonal elements, creating mutual
resistances.
Summary: Mutual resistances are
created by shared conductors (typically
ground returns) in port/net definitions.
These are typically avoided in some
formulations where ports are defined across
each conductor (net). However, those
definitions come at the cost of only being
valid at static or quasi-static
limits.
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Passivity
A question may arise as to whether the
cross-resistance can have arbitrary sign, and what this does
to passivity. Depending on the current flow, it is true that
the cross-resistance may be positive or negative (much like
mutual inductance, but unlike mutual capacitance). However,
it is easy to show that passivity is not violated by the
sign change.
The cross term contribution to power
created by the off-diagonal resistance term
is equal to the
product of the induced voltage in net I due to the current in net
j times the current in net I :

If this is positive , passivity is
preserved. Assume we start with a case where all 3 terms
have the same positive sign. Now let us change the current
direction convention in either net. As can be seen by the
definition of the off-diagonal admittance/resistance terms
defined earlier, this will have the effect of changing the
sign of
if either current
changes sign, but not if both change sign. Therefore the
product of the 3 terms will continue to remain positive,
ensuring passivity.
Summary: Mutual
resistances can have arbitrary sign. However, the signs of
the resistances, and the signs of the currents flowing
through the two associated nets are linked such that the
power loss associated with the mutual resistance is always
positive and passivity is maintained.
The fallacy of an induced resistive coupling term at high (or
low) frequencies
Confusion often arises in EM modeling
circles and in some competing products as to the definition
of off-diagonal resistances at high frequency. The argument
runs as follows: An excited port on net 1 generates a field
on net 2 (especially at high frequency). Since net 2 is
lossy, the induced field generates a current which
experiences travel through a lossy net. This is the
justification for the resistive cross coupling. The simple
fallacy is that the cross-coupling is actually through the
induced field, not the loss! It is the mutual inductive (or
capacitive) coupling that generates the induced field. The
resulting induced current then experiences loss through
the selfresistance of net 2.
Summary: There is no physical
meaning or justification of an “induced” resistive loss. The
mutual capacitance and inductance generate a current which
experiences loss due to the self resistance of the victim
net.
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